1. 298,15 :
NaH () + H2O () = NaOH () + H2 ().
. (1.22):
DG0=DG0H2() + DG0NaOH () DG0H2O () DG0NaH() =
= 0 + (495,9) (285,8) (56,4) = 153,7 .
DG , 298,15 .
2. , DG> 0, ?
. , , DG > 0, (DG !), . , . : H2Te, SiH4, NO2.
3. , 298,15 r2O3 () ?
. , , DG :
1) Cr2O3() + 3Mg() = 3MgO() + 2Cr();
2) Cr2O3() + 2Al() = Al2O3() + 2Cr();
DG01= 2DG0Cr() + 3DG0MgO() 3DG0Mg() DG0Cr2O3() =
= 3DG0MgO() DG0Cr2O3() = 3(569,3) (1059,0) = 648,9 ;
DG02= DG0Cr() + DG0Al2O3() 2DG0Al() DG0Cr2O3() =
= DG0Al2O3() DG0Cr2O3() = 1582,3 (1059,0) = 523,3 .
r2O3() r() 298,15 Mg, 1; , DG0 Mg , , .
4. WO3() .
. 298,15 :
WO3() + 3H2() = W() + 3H2O();
DG0298,15 = 3DG0H2O() + DG0W() 3DG0H2() DG0WO3() =
= 3DG0H2O() DG0WO3() = 3(228,6) (763,8) = 78,0 ;
DH0298,15= 3DH0H2O() + DH0W() 3DH0H2() DH0WO3() =
= 3DH0H2O() DH0WO3() = 3(241,8) (842,7) = 117,3 ;
DS0298,15= 3S0H2O() + S0W() 3S0H2() S0WO3() =
= 3×188,7 + 32,7 3×130,5 76 = 131,3 /.
, 298,15 . , , , (DS0298,15K) , . DG0T= 0. D0 DS0 , , , :
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D0TD0298; DS0TDS0298.
,
DG0T= D0T TDS0T
DG0TD0298,15 TDS0298,15 .
DG0T = 0, :
DH0298,15 TDS0298,15 = 0;
6200.
, 620 WO3() .